NTA Abhyas 2020
- Exam
- NTA Abhyas
- Year
- 2020
- Subject
- Chemistry
- Chapter
- Carboxylic Acid Derivatives
NTA Abhyas 2020 · Chemistry · Carboxylic Acid Derivatives
Identify A and B in the reaction given below: Ethanenitrile → _ aq...
Identify A and B in the reaction given below:
\text{Ethane}\text{nitrile}\mathop{→}_{\text{aq}{\text{.H}_{2} {\text{SO}_{4}}^{\text{Hydrolysis}} \text{A}\mathop{→}_{\text{Sodalime}^{\text{Decarboxylation}}
\text{Ethane}\text{nitrile}\mathop{→}_{\text{aq}{\text{.H}_{2} {\text{SO}_{4}}^{\text{Hydrolysis}} \text{A}\mathop{→}_{\text{Sodalime}^{\text{Decarboxylation}}
Options
- AEthanoic acid, Methane
- BEthanoic acid, Ethane
- CAcetone, Methane
- DAcetic acid, Methanol
Correct answer
A. Ethanoic acid, Methane
Step-by-step solution
Alkyl cyanides are generally named as nitriles of acids which they produce on hydrolysis. The ending ic acid of common name of the acid is replaced by term nitrile and the letter 'O' is inserted in between. For example:
\mathop{{\text{CH}_{3} - \text{CN}_{\text{Acetonitrile}} \overset{{\text{(H}_{2} \text{O)}}{→} \mathop{{\text{CH}_{3} \text{COOH}_{\text{Acetic}\text{acid}}
So, the compound is Ethanoic acid.
\mathop{{\text{CH}_{3} \text{COOH}_{\text{Sodium}\text{acetate}} \text{+}\mathop{\text{NaOH}_{\text{Sodium}\text{Hydroxide}} \mathop{→}_{\text{CaO}^{Δ} \mathop{{\text{CH}_{4}}_{\text{Methane}} \text{+}\mathop{{\text{Na}_{2} {\text{CO}_{3}}_{\text{Sodium}\text{carbonate}}
So, the compound is Methane.
\mathop{{\text{CH}_{3} - \text{CN}_{\text{Acetonitrile}} \overset{{\text{(H}_{2} \text{O)}}{→} \mathop{{\text{CH}_{3} \text{COOH}_{\text{Acetic}\text{acid}}
So, the compound is Ethanoic acid.
\mathop{{\text{CH}_{3} \text{COOH}_{\text{Sodium}\text{acetate}} \text{+}\mathop{\text{NaOH}_{\text{Sodium}\text{Hydroxide}} \mathop{→}_{\text{CaO}^{Δ} \mathop{{\text{CH}_{4}}_{\text{Methane}} \text{+}\mathop{{\text{Na}_{2} {\text{CO}_{3}}_{\text{Sodium}\text{carbonate}}
So, the compound is Methane.