NTA Abhyas JEE Main2020ChemistryCarboxylic Acid DerivativesPractice
Match list I with list II and select the correct answer using the codes given below the lists. List I (Reactions) List II (Products) ( p ) C H 2 = C H C O O H + H 2 / N i → 1 . trans- P h C H = C H O O H ( q ) c i s - C H 3 C H = C H C O O H + B r 2 / C C l 4 → 2 . racemic-2,3-dibromobutanoic acid ( r ) C 6 H 5 CH(OH)CH 2 COOH + H + → Δ 3 . C H 3 C H 2 C O O H ( s ) o - H O O C C 6 H 4 C H 2 O H + H + → Δ 4 .
Options
- A(p)-3, (q)-4, (r)-2, (s)-1
- B(p)-2, (q)-3, (r)-1, (s)-4
- C(p)-3, (q)-2, (r)-1, (s)-4
- D(p)-3, (q)-2, (r)-4, (s)-1
Correct answer
C. (p)-3, (q)-2, (r)-1, (s)-4
Step-by-step solution
The reactions are as follows