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NTA Abhyas JEE Main2020ChemistryChemical Bonding and Molecular StructurePractice

The geometry of X e O F 4 by VSEPR theory is:

Options

  1. ATrigonal bipyramidal
  2. BSquare pyramidal
  3. CPentagonal planar
  4. DOctahedral

Correct answer

B. Square pyramidal

Step-by-step solution

H = 1 2 V + M - C + A = 1 2 8 + 4 = 6 s p 3 d 2 hybridization 4 B.P + 1 B.P (Doubly bonded) + 1 L.P Square pyramidal Oxygen atom doubly bonded to Xe lone pair of electrons on axial position.

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