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Species like SbCl 6 - , SnCl 6 2 − , XeF 5 + and IO 6 5 - has hybridization as sp 3 d x - 1 . The value of “x” is

Correct answer

3.00

Step-by-step solution

Finding the number of hybridized orbitals (by using the formula) in the central atom to find the hybridization: H = 1 2 V + M - C + A SbCl 6 - ⇒ H = 1 2 ( 5 + 6 + 1 ) = 6 , sp 3 d 2 SnCl 6 2 - ⇒ H = 1 2 ( 4 + 6 + 2 ) = 6 , sp 3 d 2 XeF 5 + ⇒ H = 1 2 ( 8 + 5 - 1 ) = 6 , sp 3 d 2 IO 6 5 - ⇒ H = 1 2 ( 7 + 0 + 5 ) = 6 , sp 3 d 2

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