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The dipole moment of HBr is 1.6 × 10 - 30 Coloumb-metre and inter-atomic spacing is 1 A o . The % ionic character of HBr is

Correct answer

10

Step-by-step solution

Charge of electron = 1.6 × 10 - 19 C Dipole moment of HBr = 1.6 × 10 − 30 C × m Inter-atomic space (distance) = 1 A o = 1 × 10 - 10 m Percentage of ionic character in HBr = D i p o l e m o m e n t o f H B r × 100 i n t e r-atomic d i s t a n c e × q = 1.6 × 10 - 30 1.6 × 10 - 19 × 10 - 10 × 100 = 10 - 30 × 10 29 × 100 = 10 - 1 × 100 = 0.1 × 100 = 10 %

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