NTA Abhyas JEE Main2020ChemistryChemical Bonding and Molecular StructurePractice
The experimental value of the dipole moment of HCl is 1 .03 D . The length of the H - Cl bond is 1 .275 Å . The percentage of ionic character in HCl is: [Given: 1 D = 10 - 18 esu cm ]
Options
- A43
- B21
- C17
- D7
Correct answer
C. 17
Step-by-step solution
% Ionic c h a r a c t e r = E x p e r i m e n t a l v a l u e o f d i p o l e m o m e n t T h e o r i t i c a l v a l u e o f d i p o l e m o m e n t × 100 = μ exp μ theo × 100 Where: μ exp = 1 .030 and μ theo = q × d d = 1 .275 Å = 1 .275 × 10 - 8 cm q = 4 .8 × 10 - 10 esu μ theo = 4 .8 × 10 - 10 × 1 .275 × 10 - 8 esu - cm = 4 .8 × 1 .275 × 10 - 18 esu - cm = 4.8 × 1.275 D 1 D = 10 - 18 esu cm % Ionic character = 1.03 4.8 × 1.275 × 100 = 17