The chlorine end of the chlorine monoxide radical carries a charge of +0.167 e. The bond length is 154.6 pm. Calculate the dipole moment of the radical in Debye units.

Step-by-step solution

μ ̄ = e . d e   =   1 .167e 1 .602   ×   10 − 19   C 1e − = 2.675 × 10 − 20   C d = 154.6   pm = 154.6   × 10 − 12   m So μ ¯ = ( 2.675 × 10 − 20 C ) ( 154.6 × 10 − 12 ) = 4.136   × 10 − 30   Cm = 4.136 × 10 − 30 3.34 × 10 − 30 = 1.24   D