NTA Abhyas JEE Main2020ChemistryChemical Bonding and Molecular StructurePractice
The dipole moment of is 1.5 D . The dipole Moment of in Debye
Correct answer
1.5
Step-by-step solution
At Para positions μ → values cancel each other So, net dipole moment is due to ortho positions μ → μ = μ 2 + μ 2 + 2 μ 2 cos 120 μ = 1 .5 D