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The dipole moment of HBr is 2.6 × 1 0 - 30 esv.cm and the interatomic spacing is 1.41 Å . The percentage of ionic character in HBr is

Options

  1. A10.5
  2. B11.5
  3. C12.5
  4. D13.5

Correct answer

B. 11.5

Step-by-step solution

Percentage ionic character = Observed dipole moment Theoretical dipole moment × 100 Theoretical dipole moment of a 100% ionic character = e × d = ( 1.6 × 1 0 - 19 C ) × ( 1.41 × 1 0 - 10 m ) = 2.256 × 1 0 - 29 % ionic character = 2 . 6 × 10 - 30 2 . 256 × 6 × 10 - 29 × 100 = 11 . 5 %

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