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NTA Abhyas JEE Main2020ChemistryChemical Bonding and Molecular StructurePractice

Incorrect statement is

Options

  1. AM g O > A l F 3 > M g F 2 : Lattice energy
  2. BL i > N a > M g : Electron affinity
  3. CS F 6 > P F 5 > S i F 4 : Lewis acidic character
  4. DS i C l 4 > S i B r 4 > S i I 4 : Decreasing order of electronegativity of S i

Correct answer

C. S F 6 > P F 5 > S i F 4 : Lewis acidic character

Step-by-step solution

Here the incorrect statement is option C as the correct order of Lewis acidic character: P F 5 > S i F 4 > S F 6 . Although, S has vaccant 3d-orbital but it cannot accept co-ordinate bond from Lewis base due to steric crowding factor as S-atom is already bonded to six F-atoms. Rest other statements are correct here.

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