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NTA Abhyas JEE Main2020ChemistryChemical Bonding and Molecular StructurePractice

S b F 5 reacts with X e F 4 to form an adduct. The shapes of cation and anion in the adduct are respectively

Options

  1. ASquare planar, trigonal bipyramidal
  2. BT-shaped, octahedral
  3. CSquare pyramidal, octahedral
  4. DSquare planar, octahedral

Correct answer

B. T-shaped, octahedral

Step-by-step solution

XeF 4 + SbF 5 → [XeF 3 ] + [SbF 6 ] − → [XeF 3 ] + sp 3 d T-Shaped + [SbF 6 ] − sp 3 d 2 octahedral As [ X e F 3 ] + has 3 bond pair and 2 lone pair of electron so it has s p 3 d hybridisation and T-shape. [ S b F 6 ] - has 6 bond pair electrons so it is s p 3 d 2 hybridise and octahedral in shape.

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