NTA Abhyas JEE Main2020ChemistryChemical Bonding and Molecular StructurePractice
Match list I with list II and select the correct answer using the codes given below. List I List II P . C S 2 1 . Bent Q . S O 2 2 . Linear R . B F 3 3 . Trigonal planar S . N H 3 4 . Tetrahedral 5 . Trigonal pyramidal
Options
- AP-2, Q-1, R-3, S-5
- BP-1, Q-2, R-3, S-5
- CP-2, Q-1, R-5, S-4
- DP-1, Q-2, R-5, S-4
Correct answer
A. P-2, Q-1, R-3, S-5
Step-by-step solution
CS 2 : S .. ..   =   C   =   S .. .. : = orientation of two electron pairs around carbon in linear. SO 2 : O .. ..   =   S ..   =   O .. .. : = orientation of three electron pairs is trigonal planar, but presence of one lone pair makes the structure bent. BF 3 : F .. .. − B | :F: − F .. .. : − NH 3 H − N .. | H − H − orientation of three electron pairs is trigonal planar, Since all electron pairs are bond pairs. Therefore, structure is trigonal planar. N H 3 H