NTA Abhyas JEE Main2020ChemistryChemical Bonding and Molecular StructurePractice
The bond order of N O molecule is
Correct answer
2.5
Step-by-step solution
Bond order = 1 2 ( N b − N a ) N b → Total number of electrons in bonding molecular orbits. N a = Total number of electrons in anti-bonding molecular orbits. NO → σ 1s 2 σ 1s *2 σ 1s 2 σ 2s *2 σ 2p z 2 π 2p x 2 = π 2p y 2 π 2p x *1 =   π 2p y *0 ⇒   Bond   order   of   NO   =   1 2 10 − 5 = 2.50