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For the reaction 3 A ⇌ C + 2 D , initially A was taken. At equilibrium the concentration of D is twice that of A. The value of K c is

Correct answer

4

Step-by-step solution

Now, 2 x 3 = 2 × C - x x = 3 C - 3 x C = 4 3 x K c = C D 2 A 3 K c = x 3 × 2 x 3 2 4 3 x - x 3 = 4 27 1 27 = 4

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