Exam

NTA Abhyas

Year

2020

Subject

Chemistry

Chapter

Chemical Equilibrium

NTA Abhyas 2020 · Chemistry · Chemical Equilibrium

For the reaction 3A ⇌ C + 2D , initially A was taken. At...

For the reaction $3A ⇌ C + 2D$, initially A was taken. At equilibrium the concentration of D is twice that of A. The value of ${K}_{c}$ is

Step-by-step solution

Now, $\dfrac{2x}{3} = 2 \times \left(C - x\right)$
$x = 3C - 3x$
$C = \dfrac{4}{3}x$
${K}_{c} = \dfrac{\left[C\right]{\left[D\right]}^{2}}{{\left[A\right]}^{3}}$
${K}_{c} = \dfrac{\dfrac{x}{3} \times {\left(\dfrac{2x}{3}\right)}^{2}}{{\left(\dfrac{4}{3}x - x\right)}^{3}} = \dfrac{\left(\dfrac{4}{27}\right)}{\left(\dfrac{1}{27}\right)} = 4$