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Initially 3 moles of ' A ' was taken in a 1 L container. The approx. moles of A left in the container when the following equilibrium established is x × 1 0 - 6 .The value of ' x ' is. 3 A ⇌ B ; K C = 8 × 1 0 15

Correct answer

5

Step-by-step solution

Now, 1 - x ( 3 x ⁡ ) 3 = 8 × 1 0 15 3 x = 5 × 1 0 - 6

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