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NTA Abhyas JEE Main2020ChemistryChemical EquilibriumPractice

Which of the following lines correctly show the temperature dependence of equilibrium constant K, for an exothermic reaction?

Options

  1. AA and D
  2. BA and B
  3. CB and C
  4. DC and D

Correct answer

B. A and B

Step-by-step solution

Δ G o = - R T ln K Δ H o - T Δ S o = - R T ln K − ΔH o RT + ΔS o R = ln K Therefore ln ⁡ K vs 1 T graph will be a straight line with slope equal to - Δ H o R . Since reaction is exothermic, therefore Δ H o itself will be negative resulting in positive slope.

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