For the reaction a + b ⇌ c + d, initially concentrations of a and b...

For the reaction

a + b ⇌ c + d,

initially concentrations of a and b are equal and at equilibrium the concentration of d will be twice of that of a. What will be the equilibrium constant for the reaction?

Correct answer

Step-by-step solution

\mathop{a}_{x} + \mathop{b}_{x} ⇌ \mathop{c}_{2x} + \mathop{d}_{2x}

{K}_{c} = \dfrac{2x . 2x}{x . x} = \dfrac{4{x}^{2}}{{x}^{2}}

{K}_{c} = 4

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