Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas JEE Main2020ChemistryChemical EquilibriumPractice

Match the column I with column II and mark the appropriate choice. Column I Column II (p) Liquid ⇌ vapour (i) Saturated solution (q) Solid ⇌ liquid (ii) Boiling point (r) Solid ⇌ vapour (iii) Sublimation point (s) Solute(s) ⇌ solute (solution) (iv) Melting point

Options

  1. A(p)-(i), (q)-(iii), (r)-(ii), (s)-(iv)
  2. B(p)-(ii), (q)-(iv), (r)-(iii), (s)-(i)
  3. C(p)-(iv), (q)-(ii), (r)-(i), (s)-(iii)
  4. D(p)-(iii), (q)-(iv), (r)-(ii), (s)-(i)

Correct answer

B. (p)-(ii), (q)-(iv), (r)-(iii), (s)-(i)

Step-by-step solution

(p) Liquid ⇌ vapour equilibrium exists at the boiling point (q) Solid ⇌ liquid equilibrium exists at the melting point (r) Solid ⇌ vapour equilibrium exists at the sublimation point (s) Solute (s) ⇌ Solute (solution) equilibrium exists in a saturated solution.

Practice Chemical Equilibrium on Quantrex Academy →

More from Chemical Equilibrium

Consider the following reactions in which all the reactants and products are present in gaseous state 2xy x₂ + y₂ K₁ = 2.5 10^5 xy + 1 2 z₂ xyz K₂ = 5 10⁻³ The value of K₃ for the 2026Solid carbon, CaO and CaCO₃ are mixed and allowed to attain equilibrium at T K. CaCO ₃(s) CaO (s) + CO ₂(g) K_ p₁ = 0.08 atm C (s) + CO ₂(g) 2 CO (g) K_ p₂ = 2 atm The partial pres 2026In a closed flask at 600 K, one mole of X₂ Y₄ (g) attains equilibrium as given below : X ₂ Y ₄(g) 2 XY ₂(g) At equilibrium, 75 % X₂ Y₄ (g) was dissociated and the total pressure is 2026One mole each of He and A(g) are taken in a 10 L closed flask and heated to 400 K to establish the following equilibrium. A(g) B(g) . K_c for this reaction at 400 K is 4.0 . The pa 2026The reaction A(g) B(g) + C(g) was initiated with the amount ' a ' of A(g) . At equilibrium it is found that the amount of A(g) remaining is (a - x) at a total pressure of p . The e 2026The values of pressure equilibrium constant recorded at different temperatures for the following equilibrium reaction have been given below A(g) B(g) + C(g) 1 T ( K ⁻¹) ₁₀ K_p 0.05 2026For the following reaction at 50° C and at 2 atm pressure, 2N₂O₅(g) 2N₂O₄(g)+O₂(g) N₂O₅ is 50 % dissociated. The magnitude of standard free energy change at this temperature is x . 2026At T(K) , the equilibrium constant of A₂(g) + B₂(g) C(g) is 2.7 10⁻⁵ . What is the equilibrium constant for 1 3 A₂(g) + 1 3 B₂(g) 1 3 C(g) at the same temperature? 2026 Full Chemical Equilibrium list All NTA Abhyas JEE Main PYQs