Exam

NTA Abhyas

Year

2020

Subject

Chemistry

Chapter

Chemical Equilibrium

NTA Abhyas 2020 · Chemistry · Chemical Equilibrium

For the reaction AB (g) ⇌ A (g) + B(g), AB is 33% dissociated at a...

For the reaction $AB$\left(g\right) ⇌ A$\left(g\right) + B\left(g\right),$ AB is 33% dissociated at a total pressure of p. Then

Step-by-step solution

$( Σn{)}_{eqlibrium} = \dfrac{2}{3} + \dfrac{1}{3} + \dfrac{1}{3} = \dfrac{4}{3}$
${K}_{p} = \dfrac{{p}_{A}{p}_{B}}{{p}_{AB}} = \dfrac{\dfrac{\dfrac{1}{3}}{\dfrac{4}{3}}p\dfrac{\dfrac{1}{3}}{\dfrac{4}{3}}p}{\dfrac{\dfrac{2}{3}}{\dfrac{4}{3}}p} = \dfrac{1}{8}p$
So $p = 8{K}_{p}$.