NTA Abhyas JEE Main2020ChemistryChemical EquilibriumPractice
The gas A 2 in the left flask allowed to react with gas B 2 present in right flask as, A 2 g + B 2 g ⇌ 2 AB g ; K c = 4 at 27 o C. What is the concentration of AB when equilibrium is established?
Options
- A1.33 M
- B2.66 M
- C0.66 M
- D0.33 M
Correct answer
C. 0.66 M
Step-by-step solution
K c = AB 2 A 2 B 2 K c = 4 x 2 2 - x 4 - x ⇒ x = 3 2 2 4 = 1.33 mole AB g = 2 × 1 .33 4 = 0 .66 M