If Δ G ° [ H I ( g ) = - 1.7 k J ] , the equilibrium constant for the reaction 2 H I ( g ) ⇌ H 2 ( g ) + I 2 ( g ) at 25 ° C is

Step-by-step solution

Δ G ° = - 2.303 R T log ⁡ K log ⁡ K = - Δ G ° 2.303 R T = - - 1 .7 × 10 3 2.303 × 8.314 × 298 = log   K = + 0.298 K 1 = K = 0.298 H 2 + I 2 ⇌ 2 H I   K 1 = ( 0.504 ) 2 2 H I ⇌ H 2 + I 2   K 2 = ? K 2 = 1 K 1 = 1 ( 0.504 ) 2 = 3. 6