NTA Abhyas JEE Main2020ChemistryGeneral Organic ChemistryPractice
Find the value of p + q 3 for given structure p = degree of unsturation (DU) q = number of 2 o carbon
Correct answer
3
Step-by-step solution
p = 2 ring + 3 π bond = 5 q = 8 , 2 ∘ carbon present in the compound p + q 3 = 2 + 8 3 = 10 3 = 3.33