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The specific rotation of a pure enantiomer is + 10 ° . The observed rotation, if it is isolated from a reaction with 30% racemisation and 70% inversion is

Options

  1. A+ 10 °
  2. B- 10 °
  3. C3 °
  4. D- 7 °

Correct answer

D. - 7 °

Step-by-step solution

Specific rotation of inverted isomer = - 10 ° Angle of rotation = ( S pecific rotation of inverted isomer ) × ( Fraction of inversion ) = - 10 × 70 100 = - 7 °

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