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NTA Abhyas JEE Main2020Chemistryp Block Elements (Group 15, 16, 17 & 18)Practice

X e O 6 4 - is octahedral whereas X e F 6 is a disordered one, because

Options

  1. Afluorine is more electronegative than oxygen
  2. BXe has a lone pair in X e F 6
  3. CX e F 6 is neutral whereas X e O 6 4 - anionic
  4. DX e - F bond has more ionic characters

Correct answer

B. Xe has a lone pair in X e F 6

Step-by-step solution

Due to the presence of six fluoride ligands and one lone pair of electrons in X e F 6 , the structure lacks perfect octahedral symmetry and is disordered. In X e O 6 4 - all the valence shell electrons of xenon are involved in the bonding with oxygen and hence, no lone pair of electrons is present. So, it has perfect octahedral geometry.

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