NTA Abhyas JEE Main2020Chemistryp Block Elements (Group 15, 16, 17 & 18)Practice
When an inorganic compound (X) having 3c-2e as well as 2c-2e bonds react with ammonia gas at a certain temperature, gives a compound (Y) isostructural with benzene. Compound (X) with ammonia at a high temperature produces a substance (Z). Which option is not correct?
Options
- A(X) is B 2 H 6
- B(Z) is known as inorganic graphite
- C(Y) is B 3 N 3 H 6
- D(Z) is soft like graphite
Correct answer
D. (Z) is soft like graphite
Step-by-step solution
Diborane, B 2 H 6 , is a compound having 3c-2e and 2c-2e bonds. B 2 H 6 + 2NH 3 → low temp . B 2 H 6 ⋅ 2NH 3 → 200 ο C B 3 N 3 H 6 Y (Y) has structure similar to benzene. It is called inorganic benzene. B 2 H 6   +   NH 3 → high   temp . (BN) x Z . (Z) is called inorganic graphite and is a hard substance.