NTA Abhyas JEE Main2020ChemistryStates of MatterPractice
For one mole of a van der Waals when b = 0 and T = 300 K, the PV vs. 1/V plot is shown below. The value of the van der Waals constant a (atm litre 2 mol -2 ) is:
Options
- A1.0
- B4.5
- C1.5
- D3.0
Correct answer
C. 1.5
Step-by-step solution
van der Waals equation for 1 mol of real gas is P + a V 2 V - b = RT Given that b = 0 ∴ P + a V 2 V = RT ∴ PV = RT - a V ........ (i) Following y = mx + c for the curve PV vs 1 V Slope = - a Slope = 21.6 - 20.1 2 - 3 = - 1.5 ∴ a = 1.5