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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
States of Matter

NTA Abhyas 2020 · Chemistry · States of Matter

For one mole of a van der Waals when b = 0 and T = 300 K, the PV...

For one mole of a van der Waals when b = 0 and T = 300 K, the PV vs. 1/V plot is shown below. The value of the van der Waals constant a (atm litre^{2} mol^{-2}) is:

For one mole of a van der Waals when b = 0 and T = 300 K, the PV vs. 1/V plot is shown below. The value of the van der

Options

  1. A1.0
  2. B4.5
  3. C1.5
  4. D3.0

Correct answer

C. 1.5

Step-by-step solution

For one mole of a van der Waals when b = 0 and T = 300 K, the PV vs. 1/V plot is shown below. The value of the van der

van der Waals equation for 1 mol of real gas is

[P+aV2][V−b]=RT\left[\text{P} + \dfrac{\text{a}}{V^{2}}\right] \left[\text{V} - \text{b}\right] = \text{RT}

Given that b = 0

∴(P+aV2)(V)=RT∴ \left(\text{P} + \dfrac{\text{a}}{V^{2}}\right) \left(\text{V}\right) = \text{RT}

∴PV=RT−aV∴ \text{PV} = \text{RT} - \dfrac{\text{a}}{\text{V}}~ ........ (i)

Following y = mx + c for the curve PV vs1V\text{PV vs} \dfrac{1}{\text{V}}

Slope=−a\text{Slope} = - \text{a}

Slope=21.6−20.12−3=−1.5\text{Slope} = \dfrac{\text{21.6} - \text{20.1}}{2 - 3} = - \text{1.5}

∴a=1.5∴ \text{a} = \text{1.5}
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