NTA Abhyas JEE Main2020ChemistryStates of MatterPractice
C O 2 gas is liquefied at 27 o C . Gas follows the following graph during liquefaction for 1 mole of C O 2 . Then which statement is (are) correct in gaseous phase will (i) The maximum density of gas is 0.1 gm/ml (ii) The density of liquid C O 2 is 1 g/ml at 60 atm. (iii) At point C 50% of C O 2 is liquefied. (iv) The compressibility factor of gas at 27 o C is always less than 1. Which of the above is/are correct
Options
- Aonly i
- Bi and ii
- Ci,ii and iii
- Dall
Correct answer
C. i,ii and iii
Step-by-step solution
A Maximum density of C O 2 in gaseous phase will be at point 'A' Now: d = P M R T = 60 × 44 R × 300 = 107 g m / l t = 0.107 g m / c c Or d = m a s s o f g a s V o l u m e o f g a s = 44 g m 440 c c = 0.1 B Density of liquid C O 2 at 60 atm (at point B) At point B there will be only liquid C O 2 . So we can find out the density of density of liquid C O 2 only at point B. d = M V = 44 0.044 = 1  gm/cc C at point C the volume will be 0.44 + 0.044 2 ≈ 0.22   L And pressure is same so obviously appr