To an evacuated vessel with movable piston under external pressure of 1 atm, 0.1 mole of He and 1.0 mole of an unknown compound (vapour pressure 0.68 atm at 0 ^ ο C ) are introduced. Considering ideal gas behaviour, the

Question

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Correct answer: 7

If external pressure is 1 atm the pressure inside the cylinder will also be equal to 1 atm.
The pressure generated by unknown compound will be fixed and equal to

0.68

atm, so the pressure generated by He will be

1 – 0.68 = 0.32

atm
Now by:

V = \dfrac{n \times R \times T}{P}

\text{V} = \dfrac{0.1 \times 0.082 \times 273}{0.32} = 7\text{L}

To an evacuated vessel with movable piston under external pressure...

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