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What will be the relation between the T 1 of gas 1 with M 1 = 56 and T 2 of gas 2 with M 2 = 44 if the average speed of gas 1 is equal to most probable speed of gas 2?

Options

  1. AT 1 = T 2 2
  2. BT 1 = T 2
  3. CT 1 = ( T 2 ) 1 2
  4. DT 1 = 1 T 2

Correct answer

B. T 1 = T 2

Step-by-step solution

c a v = 8 R T π M ; c m p = 2 R T M Given that, 8 R T 1 π M 1 = 2 R T 2 M 2 8 T 1 π M 1 = 2 T 2 M 2 4 T 1 π × 56 = T 2 44 T 1 T 2 = 56 × π 44 × 4 = 1 T 1 = T 2

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