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For real gases, the relation between P, V and T is given by van der Waals equation, P + a n 2 V 2 V - n b = n R T . For the following gases C H 4 , C O 2 , O 2 , H 2 which gas will have (i) highest value of 'a' and (ii) lowest value of 'b' respectively?

Options

  1. A(i) C O 2 , (ii) H 2
  2. B(i) C H 4 , (ii) C O 2
  3. C(i) H 2 , (ii) C O 2
  4. D(i) O 2 , (ii) H 2

Correct answer

A. (i) C O 2 , (ii) H 2

Step-by-step solution

(i) Order of intermolecular attraction is C O 2 > C H 4 > O 2 > H 2 In C O 2 value of 'a' will be maximum (ii) Size increases in order of H 2 < O 2 < C H 4 < C O 2 Hence, H 2 will have lowest value of 'b'.

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