For real gases, the relation between P, V and T is given by van der Waals equation, $\left(P + \dfrac{an^{2}}{V^{2}}\right)\left(V - nb\right) = nRT .$ For the following gases $C{H}_{4}, C{O}_{2}, {O}_{2}, {H}_{2}$ which gas will have
(i) highest value of 'a' and (ii) lowest value of 'b' respectively?

Question

For real gases, the relation between P, V and T is given by van der Waals equation,

\left(P + \dfrac{an^{2}}{V^{2}}\right)\left(V - nb\right) = nRT .

For the following gases

C{H}_{4}, C{O}_{2}, {O}_{2}, {H}_{2}

which gas will have
(i) highest value of 'a' and (ii) lowest value of 'b' respectively?

Quantrex Academy · Accepted Answer

Correct answer: A. (i) C O _ 2 , (ii) H _ 2

(i) Order of intermolecular attraction is C O _ 2 > C H _ 4 > O _ 2 > H _ 2 In C O _ 2 value of 'a' will be maximum (ii) Size increases in order of H _ 2 Hence, H _ 2 will have lowest value of 'b'.

For real gases, the relation between P, V and T is given by van der...

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