NTA Abhyas JEE Main2020ChemistryStates of MatterPractice
The composition of the equilibrium mixture for the equilibrium C l 2 ⇌ 2 C l at 1470 K diffuses 1.16 times as fast as Krypton (84) under the same conditions. Find the degree of dissociation of C l 2 at equilibrium.
Options
- A0.14
- B0.41
- C0.91
- D0.24
Correct answer
A. 0.14
Step-by-step solution
C l 2 1 - x ⇌ 2 C l 2 x M m i x = ( 1 - x ) 71 + 2 x × 35.5 ( 1 - x ) + 2 x = 71 1 + x R m i x R K r = M K r M m i x 1.16 = 84 71 1 + x On solving x = 0.14