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At STP, a container has 1 mole of Ar, 2 moles of C O 2 , 3 moles of O 2 and 4 moles of N 2 without changing the total pressure if one mole of O 2 is removed, the partial pressure of O 2

Options

  1. Ais changed by about 26%
  2. Bis halved
  3. Cis unchanged
  4. Dchanges by 30%

Correct answer

A. is changed by about 26%

Step-by-step solution

In the first case, n A r = 1 , n C O 2 = 2 , n O 2 = 3 , n N A = 4 So total number of moles = 1 + 2 + 3 + 4 = 10 If P in the total pressure, P O 2 = 3 P 10 In the second case, n O 2 = 2 , n t o t a l = 9 As P remains the same, P O 2 = 2 P 9 So decrease in partial pressure of O 2 = 3 P 10 - 2 P 9 = 7 P 90 So % decrease in partial pressure of O 2 = 7 P 90 3 P 10 × 100 = 700 27 = 26 %

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