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Equal weights of two gases of molecular weight 4 and 40 are mixed. The pressure of the mixture is 1.1 atm. The partial pressure of the light gas in this mixture is

Correct answer

1

Step-by-step solution

Number of mol of gas 1 = w 4 Number of mol of gas 2 = w 40 Mole fraction of gas 1, X 1 = w 4 w 4 + w 40 = 10 11 Partial pressure of gas 1 = mol fraction of gas 1 × Total pressure = 10 11 × 1.1 atm = 1 atm

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