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The root mean square of gas molecules at 25 K and 1.5 bar is 100 m s - 1 . If the temperature is raised to 100 K and the pressure to 6.0 bar, the root mean square speed becomes

Options

  1. A200 m s - 1
  2. B100 m s - 1
  3. C400 m s - 1
  4. D1600 m s - 1

Correct answer

A. 200 m s - 1

Step-by-step solution

u rms u rms ′ = 3 RT M 3 RT' M = T T' So 100 m / s u r m s ′ = 25 K 100 K = 1 2 or u r m s ′ = 2 × 100 m s - 1 = 200 m s - 1 .

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