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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
States of Matter

NTA Abhyas 2020 · Chemistry · States of Matter

Which of the following graphs correctly represents the variation of...

Which of the following graphs correctly represents the variation of \beta=−1VdVdP\text{\beta}\text{=} - \dfrac{1}{V} \dfrac{\text{dV}}{\text{dP}} with P for an ideal gas at constant temperature?Which of the following graphs correctly represents the variation of β= - (1)/(V) dV dP with P for an ideal gas atWhich of the following graphs correctly represents the variation of β= - (1)/(V) dV dP with P for an ideal gas atWhich of the following graphs correctly represents the variation of β= - (1)/(V) dV dP with P for an ideal gas atWhich of the following graphs correctly represents the variation of β= - (1)/(V) dV dP with P for an ideal gas at

Options

  1. ATwo identical spheres each of mass 2kg and radius 50cm are fixed at the ends of a light rod so that the separation
  2. BTwo identical spheres each of mass 2kg and radius 50cm are fixed at the ends of a light rod so that the separation
  3. CTwo identical spheres each of mass 2kg and radius 50cm are fixed at the ends of a light rod so that the separation
  4. DTwo identical spheres each of mass 2kg and radius 50cm are fixed at the ends of a light rod so that the separation

Correct answer

A. Two identical spheres each of mass 2kg and radius 50cm are fixed at the ends of a light rod so that the separation

Step-by-step solution

PV = Constant
On differentiating both sides, we get
PdV + VdP = 0
PdV = -VdP
dVdP=−VP\dfrac{dV}{dP} = - \dfrac{V}{P}
1P=−1VdVdP=\beta\dfrac{1}{P} \text{=} - \dfrac{1}{V} \dfrac{\text{dV}}{\text{dP}} \text{=}\text{\beta}
Since β=1P\beta = \dfrac{1}{P} ; inverse relation result into rectangular hyperbola.
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