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Which of the following graphs correctly represents the variation of β   =   − 1 V   dV dP with P for an ideal gas at constant temperature?

Correct answer

0

Step-by-step solution

PV = Constant On differentiating both sides, we get PdV + VdP = 0 PdV = -VdP d V d P = - V P 1 P = − 1 V dV dP = β Since β = 1 P ; inverse relation result into rectangular hyperbola.

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