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The work done in an open vessel at 300 K , when 112 g iron reacts with dil. HCl is ( R = 2 cal mol - 1 K - 1 )

Options

  1. A1200   cal
  2. B600 cal
  3. C300 cal
  4. D200 cal

Correct answer

A. 1200   cal

Step-by-step solution

Fe + 2 HCl → FeCl 2 + H 2 1 mol 1 mol 1 1 2 5 6 = 2 mol 2 mol Now, V 2 = V H 2 and V 1 = 0 (For solid + aqueous state) Work done = - p ext Δ V = − Δ ( P V ) = − n H 2 R T = - 2 × 2 × 3 0 0 = - 1200 cals (Work of expansion)

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