Standard entropies of X 2 , Y 2 and XY 3 are 60 , 30 and 50 JK − 1 mol − 1 respectively. For the reaction 1 2 X 2 + 3 2 Y 2 ⇌ XY 3 , ΔH = − 30 kJ to be at equilibrium, the temperature should be:

Step-by-step solution

ΔS for the reaction 1 2 X 2 + 3 2 Y 2 ⇌ XY 3 ΔS   =   50 − 1 2   ×   60   +   3 2   ×   30 = − 25   J For equilibrium ΔG   =   0   =   ΔH − TΔS T   =   ΔH ΔS   =   − 30000 − 25   =   1200   K