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NTA Abhyas JEE Main2020ChemistryThermodynamics (C)Practice

One mol of an ideal gas was taken from A → B as shown in given figure. Magnitude of work involved in process is R = 25 3 J m o l K :

Options

  1. A5 k J
  2. B7.5 k J
  3. C2.5 k J
  4. DNone of these

Correct answer

C. 2.5 k J

Step-by-step solution

w = - n R Δ T = - 1 × 25 3 × 300 = - 2500 J

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