Combustion of glucose takes place according to the equation C 6 H 12 O 6 + 6 O 2 → 6 CO 2 + 6 H 2 O; ΔH = − 72 kcal/mol . How much energy will be released by the combustion of 1 .6 g of glucose (Molecular mass of glucose = 180 g/mol )?

Step-by-step solution

Combustion of glucose takes place according to the equation C 6 H 12 O 6   +   6O 2   →   6CO 2   +   6H 2 O;   ΔH   =   -72   kcal ΔH per 1 .6 g = 72×1 .6 180 = 0 .64 kcal