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NTA Abhyas JEE Main2020ChemistryThermodynamics (C)Practice

2 moles of solid benzoic acid undergoes combustion at 300 K . C 6 H 5 COOH s + 15 2 O 2 g → 7 CO 2 g + 3 H 2 O l . The value of Δ H – Δ U value is

Options

  1. A- 1.247 k J
  2. B- 2.494 k J
  3. C+ 2.494 k J
  4. D+ 1.247 k J

Correct answer

B. - 2.494 k J

Step-by-step solution

C 6 H 5 COOH s + 15 2 O 2 g → 7 CO 2 g + 3 H 2 O l Δ H – Δ U = Δ n g R T = – 1 2 ( 8.314 ) × 300 1000 = − 1.247 kJ for two moles it is − 2.494   kJ

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