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If heat of dissociation of C H C l 2 C O O H is 0.7 k c a l / m o l e , the, Δ H for the reaction C H C l 2 C O O H + K O H → C H C l 2 C O O H + H 2 O is

Options

  1. A– 13  kcal
  2. B+ 13  kcal
  3. C– 14.4  kcal
  4. D– 13.7  kcal

Correct answer

A. – 13  kcal

Step-by-step solution

Enthalpy of neutralization of strong acid and strong base is − 13.7 kcal/mol Δ H = – 13.7 + 0.7 = – 13.0 kcal

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