Two moles of a gas expand reversibly and isothermally at temperature of 300 K . Initial volume of the gas is 1 L while the final pressure is 4 .926 atm . The work done by gas is

Step-by-step solution

To calculate final volume V 2 = n × R × T P 2 V 2 = 2 × 0.0821 × 300 4.926 = 10   L Now, V 1 = 1   L , V 2 = 10   L,   T = 300   K,   n = 2  mole W = − 2.303   nRT   log V 2 V 1 = - 2.303 × 2 × 8.314 × 300 × log ⁡ 10 1 = - 11488.28 J