NTA Abhyas JEE Main2020ChemistryThermodynamics (C)Practice
One mole of a non-ideal gas undergoes a change of state from (2 .0 atm, 3 .0 L, 100 K) to (4 .0 atm, 5 .0 L, 250 K) with a change in internal energy, ΔU = 30 .0 Latm . The change on enthalpy of process (in L-atm) is
Correct answer
44
Step-by-step solution
Δ H = Δ U + P 2 V 2 - P 1 V 1 = 30 + 4 × 5 − 2 × 3 = 44 Latm