NTA Abhyas JEE Main2020ChemistryThermodynamics (C)Practice
The entropy change when an ideal gas under atmospheric condition at room temperature is allowed to expand from 0 .5 L to 1 .0 L and also is simultaneously heated to 373 K will be (Given: C v, m = 12 .50 J K − 1 mol − 1 and log 1 .25 = 0 .1 )
Options
- A0.18 J K - 1
- B0.36 J K - 1
- C0.90 J K - 1
- D0.72 J K - 1
Correct answer
A. 0.18 J K - 1
Step-by-step solution
n = P V R T = 0.02 moles ΔS = nRln V 2 V 1 + nC v,m ln T 2 T 1 ΔS = 0 .12 + 0 .06 ΔS = 0 .18 JK − 1