NTA Abhyas JEE Main2020ChemistryThermodynamics (C)Practice
Two moles of a gas at 8.21 bar and 300 K are expanded at constant temperature up to 2.73 bar against a constant pressure of 1 bar. How much work (in Latm) is done by the gas? (neglect the sign)
Correct answer
12
Step-by-step solution
V 1 = 2 × 0.0821 × 300 8.21 = 6.0 L V 2 = 2 × 0.0821 × 300 2.73 = 18.0 L W i r r , i s o t h e r m a l = - P e x t × Δ V = - 1 × ( 18 - 6 ) = - 12 L a t m