The enthalpy of neutralisation of NH 4 OH and CH 3 COOH is -10.5 kcal mol -1 ​ and enthalpy of neutralisation of CH 3 COOH with strong base is -12.5 kcal mol -1 .The enthalpy of ionisation of NH 4 OH will be

Step-by-step solution

Δ H ⁡ neutr. for strong acid with strong base = - 1 3 · 7 kcal equiv -1 Enthalpy of ionisation of acetic acid & NH 4 OH together = − 10 .5 − ( − 13 .7 ) = + 3 .2 kcal mol -1 Enthalpy of ionisation of only acetic acid = − 12 .5 − ( − 13 .7 ) = + 1 .2 kcal mol -1 Enthalpy of ionisation of only NH 4 OH = 3 .2 − 1 .2 = 2 kcal mol -1