NTA Abhyas JEE Main2020ChemistryThermodynamics (C)Practice
2 Z n + O 2 → 2 Z n O ; Δ G ° = - 616 J 2 Z n + S 2 → 2 Z n S ; Δ G ° = - 293 J S 2 + 2 O 2 → 2 S O 2 ; Δ G ° = - 408 J Δ G ° for the following reaction 2 Z n S + 3 O 2 → 2 Z n O + 2 S O 2 is
Options
- A- 731 J
- B- 1317 J
- C- 501 J
- D+ 731 J
Correct answer
A. - 731 J
Step-by-step solution
For the reactions, 2 Z n S → 2 Z n + S 2 ; Δ G ° = + 293 J ...(i) 2 Z n + O 2 → 2 Z n O ; Δ G ° = - 616 J ...(ii) S 2 + 2 O 2 → 2 S O 2 ; Δ G ° = - 408 J ...(iii) The Δ G ° for the reaction, 2 Z n S + 3 O 2 → 2 Z n O + 2 S O 2 can be obtained by adding equations. (i), (ii) and (iii) So, Δ G ° = 293 - 616 - 408 = - 731 J