The combustion of benzene l gives C O 2 g and H 2 O l . Given that heat of combustion of benzene at constant volume is - 3263.9 k J m o l - 1 heat of combustion (in kJ m o l - 1 ) of benzene at constant pressure will be R = 8.314 J K - 1 m

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The combustion of benzene l gives C O 2 g and H 2 O l . Given that heat of combustion of benzene at constant volume is - 3263.9 k J m o l - 1 heat of combustion (in kJ m o l - 1 ) of benzene at constant pressure will be R = 8.314 J K - 1 m o l - 1

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Correct answer: A. - 3267.6

C 6 H 6 l + 15 2 O 2 g → 6 C O 2 g + 3 H 2 O l Δ n g = 6 - 15 2 = - 3 2 Δ H = Δ U + Δ n g R T Δ H = - 3263900 - 3 2 × 8.314 × 298 J = - 3267616 J = - 3267.616 k J

The combustion of benzene l gives C O 2 g and H 2 O l . Given that heat of combustion of benzene at constant volume is - 3263.9 k J m o l - 1 heat of combustion (in kJ m o l - 1 ) of benzene at constant pressure will be R = 8.314 J K - 1 m o l - 1

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