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What will be the entropy change of the system when expansion of 1 mole of a gas takes place from 3 L to 6 L under isothermal conditions? Consider, R = 2 cal K - 1 m o l - 1 and log ⁡ 2 = 0.301 .

Options

  1. A2.84 cal K - 1
  2. B1.386 cal K - 1
  3. C0.37 cal K - 1
  4. D5.26 cal K - 1

Correct answer

B. 1.386 cal K - 1

Step-by-step solution

n = 1 , V i = 3 L , V f = 6 L Δ S = 2.303 n R log 10 ⁡ V f V i Δ S = 2.303 × 1 × 2 log ⁡ 6 3 = 2.303 × 2 × 0.3010 = 1.386 cal K - 1

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