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A given mass of gas expands from state A to state B by three paths 1, 2 and 3 as shown in the figure If w 1 , w 2 and w 3 respectively are be the works done by the gas along three paths, then

Options

  1. Aw 1 > w 2 > w 3
  2. Bw 1 < w 2 < w 3
  3. Cw 1 = w 2 = w 3
  4. Dw 1 < w 2 ; w 1 < w 3

Correct answer

B. w 1 < w 2 < w 3

Step-by-step solution

Work is equal to area under P - V graph (when P is plotted along y-axis). As area under graph 3 is maximum and area under graph 1 is minimum, so w 3 is maximum and w 1 is minimum. So w 1 < w 2 < w 3

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